0.01x^2=0.005x^2+2

Solution for 0.01x^2=0.005x^2+2 equation:

0.01x^2=0.005x^2+2

We move all terms to the left:

0.01x^2-(0.005x^2+2)=0

We get rid of parentheses

0.01x^2-0.005x^2-2=0

We add all the numbers together, and all the variables

0.005x^2-2=0

a = 0.005; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·0.005·(-2)
Δ = 0.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.04}}{2*0.005}=\frac{0-\sqrt{0.04}}{0.01}
=-\frac{\sqrt{}}{0.01}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.04}}{2*0.005}=\frac{0+\sqrt{0.04}}{0.01}
=\frac{\sqrt{}}{0.01}
$